Question

32 x 10^5 dyne is applied on an stationary object of 40 kg. After 2 minutes what will be it's momentum.

Answer 1

1 dyne=10^-5 N

32*10^5 dyne=32 N

u=0

t=2*60

=120 sec

therefore

initial momentum=pi=0

also

F*t=pf-pi

F*t=pf

pf=32*120

=3840 kg m/s

Hope this helps