Question

4x^3-3x^2+4/x^2-8 find differentiation

Answer 1

y=4x^3-3x^2+4/x^2-8

d(x^n)/dx=n(x^(n-1))

d(constant)/dx=0

therefore

dy/dx=12x^2-6x-2/x^3+0

=12x^2-6x-2/x^3

hope this helps