33. A man drives his car with uniform speed from place A to the place B which is 150 km away. Again
he returns to the place A by increasing the speed of the car 10 km/hour and there by reaches 30
minutes earlier than the time taken in his forward journey. Find the total time taken by him in
forward and return journey.
Answers
Answered by
9
Answer:
The total time required in the entire journey is 5.5 hours.
Step-by-step explanation:
Distance= 150km
Let the original speed be S, so the new speed is S+10
Original time = 150/S
New time = 150/( S+10)
Difference between both the time taken= 30 minutes or 1/2 hours.
So, according to the given conditions, we can form the equation as:
150/S - 150/( S+10) = 1/2
So, by solving this we get the equation
S2+ 10S- 3000= 0
So, on solving it, we get S as 50
Original speed is 50km/hour , so new speed is 60 km/hour
So, original time is 150/50 = 3hours
New time is 150/60 = 2.5 hours
So, total time taken = 5.5 hours
Hope it helps you
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