Question

33. In the given figure, ABCD is a
trapezium in which AB||DC, AB is
a diameter and angleCAB = 28°, The
difference of angleADC and angleABC is
D
28°
​

Answer 1

Answer:

ab is the diameter

So semicircular

∠

a

c

b

=

90

∘

Given

∠

c

a

b

=

28

∘

So

∠

a

b

c

=

90

∘

−

28

∘

=

62

∘

Now

∠

a

d

c

+

∠

a

b

c

=

180

∘

So

∠

a

d

c

=

180

∘

−

62

∘

=

118

∘

So the difference between

∠

a

d

c

−

∠

a

b

c

=

118

∘

−

62

∘

=

56

∘