35% candidates failed in one subject and 42% failed in another subject while 15% failed in both the subject is 2500 candidate appeared at the exam how many passed in either subject but not in both
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actual candidate=2500
paper1 failed student = 35
paper2 failed student = 42
student failed on both = 15
assume no of candidate = 100
paper 1 passed student = 100-35=>65
paper 2 passed student = 100-42=58
students failed in paper1 only=35-15=20
students failed in paper2 only=42-15=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate Passed in paper2 only=58-38=20
either passed in paper1 & 2 = 27+20 =47
but actual student = 2500 in question
so 2500 *47/100 =1175
please mark as brainliest
paper1 failed student = 35
paper2 failed student = 42
student failed on both = 15
assume no of candidate = 100
paper 1 passed student = 100-35=>65
paper 2 passed student = 100-42=58
students failed in paper1 only=35-15=20
students failed in paper2 only=42-15=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate failed both paper=20+27+15=62
candidate Passed both paper=100-62=38
candidate Passed in paper1 only = 65-38=27
candidate Passed in paper2 only=58-38=20
either passed in paper1 & 2 = 27+20 =47
but actual student = 2500 in question
so 2500 *47/100 =1175
please mark as brainliest
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