Question

36. One girl calculates that her chance of winning the first prize in the lottery are 0.08. If 6000 tickets were
sold, how many tickets would he have bought ?​

Answer 1

Answer:

then I'm going to get your phone on the same way and not a same way

Answer 2

Answer:

Total number of sold tickets are 6000.

So n(S) = 6000

Let she bought x tickets

So n(E) = x

Probability of winning the first prize in a lottery is 0.08

So P(E) = 0.08

As P(E) = n(E)/n(S)

So 0.08 = x/6000

x = 6000 X 0.08

x = 480

Hence, she bought 480 tickets.

Step-by-step explanation:

I hope it will help you to proceed further....

@mandalsneha