37. A tree is broken at a height of 24 m from the ground The top of the tree touches the ground at the distance of 7 m away from the foot of the tree. Then, find the actual height of the tree. A. 32 m B. 27 m C. 49 m D. 48m
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Answer:
C.49m
Step-by-step explanation:
Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.
AB=24m and BC=7m
Using Pythagoras theorem, In ΔABC
(AC)²=(AB)²+(BC)²
⇒(AC)²=(24)²+(7)²
⇒(AC)2=576+49
⇒(AC)²=625
⇒AC=25m
Hence, the total height of the tree=AC+CB=25+24=49m.
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