Question

39. ABC is a right angled triangle, right angled at
B. If AD = CD and A DBC = 20°, find ABAC​

Answer 1

Answer:

it will be A form it

Step-by-step explanation:

it's 70. of it

Answer 2

Value of  angle $\angle CAB = 30^\circ$

Step-by-step explanation:

Given that,

ABC is a right angle triangle, at angle $\angle B$

                     $AD= CD$

                 and $\angle DBC = 20 ^{\circ}$

First draw a right angle triangle ABC and divided side AC in such

a way that $AD = CD$

Now consider   ,

As we know that

The addition of all angles of a triangle is $180^\circ$

So,

           $\angle DBC+ \angle DCB+ \angle BCD= 180^\circ$

                      $90^\circ+ \angle DCB+ 20^\circ= 180^\circ$

                         $\angle DCB = 70^\circ$

Now,

            In $\Delta ABC,$  

we know that the addition of all angles of a triangle is $180^\circ$

                    $\angle ABC + \angle BCA + \angle CAB=180^\circ$

          Putting the value of angles

                   $90^\circ+70^\circ+\angle CAB=180^\circ$

                       $160^\circ + \angle CAB = 180^\circ$

                         $\angle CAB = 30^\circ$

Thus, the value of  $\angle CAB = 30^\circ$