Q65l of body is thrown vertically upward with an initial velocity of
100 ml$. find the time takeń to reach the maximum
height and the marrimum height reached.
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Answer:
m = 65 kg
u = 10 m / s.
v = 0 at max height.
Therefore,
v - u = - 2gh
0 - 10 =-( 2 × 10 × h)
10 =20h
h = 0.5 m
The time taken:-
v - u = -gt
(v - u)/-g = t
0 - 10/(-10)= t
t = 1 s
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