3a^2 + 12b^2 -12ab
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= 3 (a² + 4b² - 4ab)
= 3 {(a)² + (2b)² - 2.a.2b}
= 3 (a - 2b)²
= 3 (a - 2b) (a - 2b)
Answered by
2
here,
take 3 common
3(a² + 4b² - 4ab) ...........(1)
now,
a ² + (2b)² - 2 (a) (2b)
= (a - 2b )²
using, (x - y)² = x² -2xy + y²
thus, equation (1) becomes
3(a-2b)² = 3 (a-2b) (a-2b) . hence,proved.
KSHITIJ
take 3 common
3(a² + 4b² - 4ab) ...........(1)
now,
a ² + (2b)² - 2 (a) (2b)
= (a - 2b )²
using, (x - y)² = x² -2xy + y²
thus, equation (1) becomes
3(a-2b)² = 3 (a-2b) (a-2b) . hence,proved.
KSHITIJ
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