Question

(3k+1) x-(2k+3) y+(9-k) =0

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Answer 1

Answer:

(3k+1)x- (2k+3)y+(9-k)=0

(3k+1)x-(2k+3y+9-k)=0

(3k+1x-2k+3y+9-k)=0

arrange the numerx,

3k-3k+x+3y+9=0

x+3y+9=0

x+3y=-9

x+y=-9/3

x+y=-3