3k^2+10k-9 divided by k-9
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1
Answer:
Given 3k
3
−10k
2
+9k−2=0=p(x)
when k=1 p(x)=0
Synthetic division
(k−1)(3k
2
−7k+2)
(k−1)(3k
2
−6k−k+2)
(k−1)[3k(k−2)−1(k−2)]
(k−1)(3k−1)(k−2)
∴ values of k are
k=
3
1
,1,2
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