3rd term of a gp is 27 and its 6th term is 729 find the product of its first and 7th terms
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ar^2=27 ---------(1)
ar^5=729--------(2)
now divide (2) by (1)
r^3=27
r=3
ar^2=27
9a=27
a=3
first term is 3
7th term :- ar^6 = 2187
now multiply first term and 7th term
2187×3=6561
so ans is 6561
hope this will help you
ar^5=729--------(2)
now divide (2) by (1)
r^3=27
r=3
ar^2=27
9a=27
a=3
first term is 3
7th term :- ar^6 = 2187
now multiply first term and 7th term
2187×3=6561
so ans is 6561
hope this will help you
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