Question

3x^2+13x+k=0 (using x=4)​

Answer 1

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3 × (4)² + 13 × 4 + K = 0

3 × 16 + 52 + K = 0

48 + 52 + K = 0

K = - 100

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Answer 2

3(4)^2 + 13(4) + k = 0

81^2 + 52 + k = 0

6561 + 52 + k = 0

6613 + k = 0

k = (-6613)