Question

The answer is 2. Please solve this sum because i have to mention full sum​

Answer 1

${7}^{2x + 1} \div 49 = 343 \\ {7}^{2x + 1} \div {7}^{2} = {7}^{3} \\ {7}^{2x + 1} = {7}^{3} \times {7}^{2} \\ {7}^{2x + 1} = {7}^{3 + 2} \\ {7}^{2x + 1} = {7}^{5} \\ 2x + 1 = 5 \\ 2x = 5 - 1 \\ 2x = 4 \\ x = 2$