3x+2y/xy=1and 4x-2y/xy=13 solve for x and y
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3x+2yx+y=1 ...(1)
4x−2yxy=13 ...(2)
From eq(1), we have3x+2yx+y=1 ⇒3x+2y=x+y
⇒2x=−y⇒y=−2xSubstitute the value of y in eq(2), we get4x−2(−2x)x(−2x)=13
⇒4x+4x=−26x2
⇒26x2+8x=0
⇒2x(13x+4)=0
⇒13x+4=0
⇒x=−413and
y=−2(−413)
⇒y=8
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