Question

(3x-4)cube-(x+1)cube divided by (3x-4)cube+(x+1)cube=61÷189

Answer 1

Heya User

∆ Love ya ! Thanks for the Question !!

Solution :

$\frac{ {(3x - 4)}^{3} - {(x + 1)}^{3} }{(3x - 4)^{3} + {(x + 1)}^{3} } = \frac{61}{189}$

Inverting and applying Componendo Dividendo :

$( \frac{3x - 4}{x + 1} )^{3} = \frac{250}{128} = \frac{125}{64}$

Taking the Cube Root of Both Sides :

$\frac{3x - 4}{x + 1} = \frac{5}{4}$

Solving the Linear Equation :

$4(3x - 4) = 5(x + 1)$

$= > 12x - 16 = 5x + 5$

$= > 7x = 21$

$= > x = 3$

Hence, x = 3 is the solution ^_^

Answer 2

Answer: not able to do

Step-by-step explanation: