Question

3x-4y-6 when x=7/3 and y=19/4

Answer 1

3(7/3)-4(19/4)-6
cancelling 3 and 4 on both sides
7-19-6
-18

Answer 2

$3x - 4y - 6 \\ = > 3 \times \frac{7}{3} - 4 \times \frac{19}{4} - 6 \\ = > 7 - 19 - 6 \\ = > 7 - 25 \\ = > - 18(ans)$
Hope it helped

Mark me as brainliest if it's correct