3x-4y=-7 & 5x2y=0 by cramers rule
Answers
Step-by-step explanation:
D=[3 -4]
[5 2]
= 3×2-5×-4
= 6+20=26
Dx= [-7 -4]
[0 2]
= -7×2-0×-4
= -14+4
= 18
Dy = [ 3 -7]
[ 5 2]
= 3×2-5×-7
= 6 +35
= 41
Answer:
The solution of the given simultaneous equations is ( x, y ) = ( 1, 5 / 2 ).
Step-by-step-explanation:
The given simultaneous equations are
3x - 4y = - 7 - - - ( 1 )
5x - 2y = 0 - - - ( 2 )
Now, comparing equation ( 1 ) with a₁x + b₁y = c₁, we get,
3x - 4y = - 7 - - - ( 1 )
- a₁ = 3
- b₁ = - 4
- c₁ = - 7
Now, comparing equation ( 2 ) with a₂x + b₂y = c₂, we get,
5x - 2y = 0 - - - ( 2 )
- a₂ = 5
- b₂ = - 2
- c₂ = 0
Now, we know that,
Refer to attachment 1.
⇒ D = 3 * ( - 2 ) - [ ( - 4 ) * 5 ]
⇒ D = - 6 - ( - 20 )
⇒ D = - 6 + 20
⇒ D = 14
Now, we know that,
Refer to attachment 2.
⇒ Dₓ = ( - 7 ) * ( - 2 ) - [ ( - 4 ) * 0 ]
⇒ Dₓ = 14 - 0
⇒ Dₓ = 14
Now, we know that,
Refer to attachment 3.
⇒ Dᵧ = 3 * 0 - [ ( - 7 ) * 5 ]
⇒ Dᵧ = 0 - ( - 35 )
⇒ Dᵧ = 0 + 35
⇒ Dᵧ = 35
Now, by Cramer's rule,
x = Dₓ / D
⇒ x = 14 / 14
⇒ x = 1
Now, by Cramer's rule,
y = Dᵧ / D
⇒ y = 35 / 14
⇒ y = 5 / 2
∴ The solution of the given simultaneous equations is ( x, y ) = ( 1, 5 / 2 ).