(3x+70)° and (x+100)° are two vertically opposite angles find the measure of each of the two angles
Answers
Answered by
15
3x + 70 = x + 100
3x - x = 100-70
2x= 30
x = 30/2
x 15
3x +70 = 3 × 15 + 70 = 45 + 70 = 115
x+ 100 = 15 +100 = 115
3x - x = 100-70
2x= 30
x = 30/2
x 15
3x +70 = 3 × 15 + 70 = 45 + 70 = 115
x+ 100 = 15 +100 = 115
Answered by
3
Since they are vertically opposite angle.... They are equal
So,
3x+70 = x+100
3x-x = 100 - 70
2x = 30
x = 30/2
x = 15°
Angles are :-
=> 3x+70
= 3×15 + 70
= 45 + 70
= 115°
=> x+100
= 15 + 100
= 115°
Follow @devadakshan
So,
3x+70 = x+100
3x-x = 100 - 70
2x = 30
x = 30/2
x = 15°
Angles are :-
=> 3x+70
= 3×15 + 70
= 45 + 70
= 115°
=> x+100
= 15 + 100
= 115°
Follow @devadakshan
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