Question

3x²+2√5x -5=0 factories​

Answer 1

Step by Step Explanation

Using Hit and Trial

x = √5

p(x) = 3x² + 2√5x - 5

p(√5) = 3(√5)² + 2√5(√5) - 5

p(√5) = 3×5 + 2×10 - 5

p(√5) = 15 + 10 - 5

p(√5) = 20

Thus, x = √5 is not the factor of p(x)

So lets put

x = -√5

p(x) = 3x² + 2√5x - 5

p(-√5) = 3(-√5)² + 2√5(-√5) - 5

p(-√5) = 3×5 - 2×5 - 5

p(-√5) = 15 - 10 - 5

p(-√5) = 15 - 15

p(-√5) = 0

Thus, x = -√5 is the factor of p(x)

Answer 2

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\red{ the \: quadratic \: formula \: x = \frac{ - b±\sqrt{ {b}^{2} -4ac } }{2a} } \\ \sf\red{ {3x}^{2} + 2 \sqrt{5}x - 5 } \\ \sf\red{ = > x = \frac{ - 2 \sqrt{5}± { \sqrt{(2\sqrt{5})^2 - 4 \times 3 \times ( - 5) } } }{2 \times 3} } \\ \sf\red{ = > x = \frac{ - 2 \sqrt{5}± \sqrt{20 + 60} }{6} } \\ \sf\red{ = > x = \frac{ - 2 \sqrt{5 }± \sqrt{80} }{6} } \\\sf\red{ = > x = \frac{ - 2\sqrt{5}.4 \sqrt{5} }{6} } \\\sf\pink{ = >x = \frac{ - 2 \sqrt{5 } + 4 \sqrt{5} }{6} } \\ \sf\pink{ = > x = \frac{2 \sqrt{5} }{6} } \\ \sf\pink{ = > x = \frac{ \sqrt{5} }{3} } \\ \sf\purple{ or \: x = \frac{ - 2 \sqrt{5} - 4 \sqrt{5} }{6} } \\ \sf\purple{ = > x = \frac{ - 6 \sqrt{5} }{6} } \\ \sf\purple{ = > x = - \sqrt{5} } \\ \large\boxed{ \fcolorbox{blue}{yellow}{hope \: it \: help \: you}}$