Math, asked by StarTbia, 1 year ago

3x²-2√6 x+2=0 Solve this quadratic equation by factorisation.

Answers

Answered by rohitkumargupta
31
3x² - 2√6x + 2 = 0
3x² - √6x - √6x + 2 = 0
√3x(√3x - √2) - √2(√3x - √2) = 0
(√3x - √2)(√3x - √2) = 0
x = √2/√3 , x = √2/√3
Answered by Anonymous
86
✴✴ \color{red}{ \bf \underline{HEY \: FRIENDS!!}}✴✴

 \color{yellow}{ \bf{-----------------------------------}}

 \color{green}{ \underline{Here \: is \: your \: answer↓}}⬇⏬⤵

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

▶⏩ \color{blue}{ \boxed{FACTORISE:-)}}

↪➡ \color{gold}{ \bf{3 {x}^{2} - 2 \sqrt{6}x + 2 = 0.}}

↪➡ \color{orange}{ \bf{3 {x}^{2} - \sqrt{6}x - \sqrt{6}x + 2 = 0.}}

↪➡ \color{orange}{ \bf{ \sqrt{3}x( \sqrt{3}x - \sqrt{2} ) - \sqrt{2} ( \sqrt{3}x - \sqrt{2} ) = 0.}}

↪➡ \color{orange}{ \bf{( \sqrt{3}x - \sqrt{2}) \: ( \sqrt{3}x - \sqrt{2} ) = 0.}}

↪➡ \color{orange}{ \bf{ \sqrt{3}x - \sqrt{2} = 0 \: | \: \sqrt{3}x - \sqrt{2} = 0.}}

↪➡ \color{orange}{ \bf{x = \frac{ \sqrt{2} }{ \sqrt{3} } \: | \: x = \frac{ \sqrt{2} }{ \sqrt{3} } .}}

✅✅ \color{blue}{ \boxed {Hence, it \: is \: factorised.}}✔✔

✴✴ \color{green}{ \bf \boxed{THANKS}}✴✴

☺☺☺ \color{red}{ \bf \underline{Hope \: it \: is \: helpful \: for \: you}}✌✌✌.

Niruru: Very tempting and well solved!
Anonymous: thanks @stager
rohitkumargupta: see your answer by site
rohitkumargupta: better don't use collor Comand
Deepsbhargav: again rock..
Deepsbhargav: xD
Anonymous: thanks
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