Question

3x²+4xy-y²
ANSWER IS ☝️☝️☝️
Simplify and verify the result for x = 2 and y = 1
(x + y)(2x + y) + (x + 2y)(x - y)​
solve and tell how answer comes ​

Answer 1

(x + y)(2x + y) + (x + 2y)(x - y)

=> (2x² + xy + 2xy +y²) + (x² - xy + 2xy -2y²)

=> 2x² + x² + xy + 2xy - xy + 2xy + y² - 2y²

=>3x² + 4xy - y²

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Answer 2

$\huge\purple{AnsWeR}$

$1)(x+y)(2x+ y) + (x+ 2y)(x— y)(x+y)(2x+y)+(x+2y)(x—y)$

$=>(x)(2x+ y)+y (2x+ y)+ (x) (x— y)+2y(x— y)$

$=>2x^2+xy+2xy+ y^2+ x^2-xy+2yx- 2y^2$

$=>3x^2+4xy- y^2$ ANSWER

•VERIFY

LHS

$(x+y)(2x+ y) + (x+ 2y)(x-y)$

x = 2 and y = 1

$=>(2+1)(2×2+1)+(2+2×1)(2-1)$

$=>(3)(4+1)+(4)(1)=>(3)(4+1)+(4)(1)$

$=>3×5+4=>15+4$

$=>19$

RHS

$3x^2+4xy-y^2$

x = 2 and y = 1

$=>(3×2^2)+(4×2×1)-1^2$

$=>(3×4)+(8×1)-1$

$=>12+8-1$

$=>20-1=>19$

HOPE SO IT IS HELPFUL..❣️✌️