3x²-5x+7=0 Determine the nature of roots for the quadratic equation
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Answered by
122
Hi ,
Compare 3x² - 5x + 7 = 0 with
ax² + bx + c = 0 , we get
a = 3 , b = -5 , c = 7
Discreaminant ( D ) = b² - 4ac
D = ( -5 )² - 4 × 3 × 7
D = 25 - 84
D = - 59
D < 0
Therefore ,
Roots of given quadratic equation
are not real.
I hope this helps you.
: )
Compare 3x² - 5x + 7 = 0 with
ax² + bx + c = 0 , we get
a = 3 , b = -5 , c = 7
Discreaminant ( D ) = b² - 4ac
D = ( -5 )² - 4 × 3 × 7
D = 25 - 84
D = - 59
D < 0
Therefore ,
Roots of given quadratic equation
are not real.
I hope this helps you.
: )
Answered by
45
{Hello}
Solution,
3x² - 5x + 7 = 0
Comparing with ax², + BC + c =0, we get,
a =3,b = - 5, c = 7
∆ =b²-4ac
=(-5)²-4×3×7
=25 - 84
.'. ∆ = -59
.'.{As ∆ <0, the root of the quadratic equation are not real }
Thank you
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