Question

-3x³y³+3/2x²y⁴ evaluate at x = 1 and y=2​

Answer 1

Answer:

$- 3 \times 1 {}^{3} ..2 {}^{4} .. \div 2 \times 1 \times...{2} ..y4 = 2 \times 2 \times 2 \times 2 = 16.. \\ \\ - 3.1.16 + 3 = 0..(x) = 1..(y)..16 =$

0.. 1,16-1,16

2 Willbe the answer

Answer 2

3×1

3

..2

4

..÷2×1×...2..y4=2×2×2×2=16..

−3.1.16+3=0..(x)=1..(y)..16=

0.. 1,16-1,16

2 Willbe the answer