Question

First term of an arithmetic sequence is 8 and the common difference is 5. Write its algebraic form.

Answer 1

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Answer 2

The required algebraic form is b = 8 + (n - 1)*5.

Step-by-step explanation:

According to the given information, the first term of an arithmetic sequence is 8 and the common difference is 5.

Now, we know that, if b is the nth term of an arithmetic sequence and a is the first or initial term of an arithmetic sequence and d is the common difference involving the terms of the sequence,

The arithmetic sequence will always follow the formula for the nth term that is,

b = a + (n - 1)d.

Now, here, putting the values that are given we get,

For a = 8 and d = 5, we get the algebraic form as,

b = 8 + (n - 1)*5

Thus, the required algebraic form is b = 8 + (n - 1)*5.

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