(3xy+ysquare)dx=(xsquare +xy)dy solve this question in integration
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dy/dx= -(3xy+y2)/(x2+xy)
put y=vx
dy/dx=v+x(dv/dx)
v+x(dv/dx)=-(3vx2+v2x2)/(x2+vx2)
v+x(dv/dx)=-(3v+v2)/(1+v)
∫((1+v)/v)dv=-∫(4/x)dx
ln(v)+v=-4lnx+c
(ln(v)+v+lnx4)=constant
ln(y/x)+lnx4+(y/x)=c.
put y=vx
dy/dx=v+x(dv/dx)
v+x(dv/dx)=-(3vx2+v2x2)/(x2+vx2)
v+x(dv/dx)=-(3v+v2)/(1+v)
∫((1+v)/v)dv=-∫(4/x)dx
ln(v)+v=-4lnx+c
(ln(v)+v+lnx4)=constant
ln(y/x)+lnx4+(y/x)=c.
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