Question

3y^2-14y+8=0 solve by factorization method

Answer 1

Hey!

3y^2 -14y +8 =0

3y^2-12y-2y+8=0.

3y(y-4)-2(y-4)=0.

(3y-2(y-4)=0.

Hope it helps.

Answer 2

Concept Introduction:

The process of factorization involves dividing mathematical algebraic formulas into the sum of their factors. When the factors are multiplied once more, the original phrase is obtained.

Given, $3y^2-14y+8=0$

To find, solve by factorization method.

Solution:

$3y^2-14y+8=0$

$3y^2 - ( 12+2)y - 8= 0$

$3y^2 - 12y - 2y + 8 = 0$

$3y ( y - 4 ) - 2 ( y - 4 ) = 0$

$( y - 4 ) ( 3y - 4 ) = 0$

Either, $( y - 4 ) = 0$ or $( 3y - 2 ) = 0$

So, $y = 4$ or $y = 2/3$

Final Answer:

The value of y is either $y=4$ or $y=2/3$

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