Math, asked by yashrajsingh931, 4 hours ago

3z+(8+3z)/3-(7z-2)=8z​

Answers

Answered by udhwanirashmi
0

Answer:

Step-by-step explanation:

3z + (8+3z) / 3 - (7z-2) = 8z

3z + 8 + 3z / 3 - 7z + 2 = 8z

6z + 8 / 5 - 7z = 8z

6z + 8 = 8z (5 - 7z)

6z + 8 = 40z - 56z

6z + 8 = -16z

8 = -16z - 6z

8 = -22z

z = - 8/22

z = - 4/11

hope it will help you

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