Question

-4.5 and -4.6, Write any three rational numbers between the given two numbers.

Answer 1

-45/10*100/100=-4500/1000&-46/10*100/100=-4600/1000
So three numbers are -4502/1000,-4509/1000,-4559/1000that is -4.502,-4.509,-4.559

Answer 2

Answer:

$t_{1}=\frac{-91}{20}$, $t_{2}=\frac{-181}{40}$ and $t_{3}=\frac{-361}{80}$

Step-by-step explanation:

In the given question,

The rational numbers between the two numbers, say, 'a' and 'b' is given by,

$1st=\frac{a+b}{2}\\2nd=\frac{a+(\frac{a+b}{2})}{2}$

So,

We have the numbers -4.5 and -4.6.

So,

The rational numbers between these two numbers is given by,

$t_{1}=\frac{-4.5+(-4.6)}{2}=\frac{-9.1}{2}\\t_{1}=-4.55\\t_{1}=\frac{-91}{20}$

The 2nd number is given by,

$t_{2}=\frac{-4.5+(-4.55)}{2}=\frac{-9.05}{2}\\t_{2}=-4.525\\So,\\t_{2}=\frac{-905}{200}=\frac{-181}{40}$

The 3rd number is given by,

$t_{3}=\frac{-4.5+(-4.525)}{2}=\frac{-9.025}{2}\\t_{3}=-4.5125\\So,\\t_{3}=\frac{-9025}{2000}=\frac{-361}{80}$

Therefore,

All the three rational numbers between -4.5 and -4.6 are,

$t_{1}=\frac{-91}{20}$, $t_{2}=\frac{-181}{40}$ and $t_{3}=\frac{-361}{80}$