4/5 tan2 60+3sin260 find the values of
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we have
4/5tan^2 60°+3sin^2 60°........1
tan 60°=√3
tan^2 60°=3
now
sin 60°=√3/2
sin^2 60°=3/4
substituting in equ 1 we get
4/5×3+3×3/4
12/5+9/4
48/20+45/20
93/20
4/5tan^2 60°+3sin^2 60°........1
tan 60°=√3
tan^2 60°=3
now
sin 60°=√3/2
sin^2 60°=3/4
substituting in equ 1 we get
4/5×3+3×3/4
12/5+9/4
48/20+45/20
93/20
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