Question

please do this............very urgent AP one

Answer 1

In an A.P., the common difference is constant

So, 2k + 1 - k + 3 = 4k + 3 - 2k - 1

=> k + 4 = 2k + 2

=> k - 2k = 2 - 4

=> -k = -2

=> k = 2

Hope this helps......

Answer 2

Given 1st term T1 = (k - 3).

Given 2nd term = (2k + 1).

Given 3rd term = (4k + 3).

Given that they are in AP.

T2 - T1 = T3 - T2

(2k + 1) - (k - 3) = (4k + 3) - (2k + 1)

2k + 1 - k + 3 = 4k + 3 - 2k - 1

k + 4 = 2k + 2

4 = 2k + 2 - k

4 = k + 2

4 - 2 = k

k = 2.


Therefore the value of k = 2.


Hop this helps!