Question

4(a+b)-6(a+b)2 factorize

Answer 1

$4(a + b) - 6(a + b) {}^{2} \\ (a + b)(4 -6 (a + b)) \\ = (a + b)(4 - 6a - 6b)$
here is your answer
....mark as brainliest if helped
or
(a+b)(4-6(a+b))
take 2 common
(a+b)(2)(2-3(a+b))
2(a+b)(2-3(a+b))
answer is correct but more simplified

Answer 2

Given,

$4(a + b) - 6(a + b) ^{2}$

To find,

The factors of the given expression.

Solution,

The factors of $4(a + b) - 6(a + b) ^{2}$ will be 2(a+b) (2-3a-3b).

We can easily solve this problem by following the given steps.

According to the question,

We have the following expression:

$4(a + b) - 6(a + b) ^{2}$

Now, we can only factorise it by taking out the common because we can not solve it using the identity method or by splitting the middle term.

Taking out (a+b) as a common factor:

(a+b) [4-6(a+b)]

(a+b)(4-6a-6b)

Taking out 2 as a common factor:

2(a+b) (2-3a-3b)

Hence, the factors of $4(a + b) - 6(a + b) ^{2}$ are 2(a+b) (2-3a-3b).