Question

4. An alternating emf'given by equation L. e = 300 sin [(100 rt)t] V is applied to a resistance 100 ohm . The rms current through the circuit is (in amperes) ​

Answer 1

Answer:

Explanation:

Here, given that Eo= 300

R=100ohm

Erms = Eo/√2

Erms=300/√2

Now, as we know that

Irms=Erms/R

Irms=300/(√2*100)

Irms=3/√2 A

Answer 2

The rms current through the circuit is 2.12 A.

Explanation:

An alternating emf given by equation :

$E=300\sin(100\pi\ t)$

Here, 300 volts is the peak voltage

RMS emf is then given by :

$E_{rms}=\dfrac{E_o}{\sqrt 2}\\\\E_{rms}=\dfrac{300}{\sqrt 2}\\\\E_{rms}=212.13\ V$

Resistance, R = 100 ohms

The rms value of current is given by :

$I_{rms}=\dfrac{E_{rms}}{R}\\\\I_{rms}=\dfrac{212.13}{100}\\\\I_{rms}=2.12\ A$

So, the rms current through the circuit is 2.12 A.

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