4 dice are rolled. Probability of not getting the same number on 3 dice.
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Total number of outcome of each dice = 6
P(getting the same number as another throw) = 1/6
first of all Find the probability of getting 3 of the same number:
Probability of getting 2 of the dice the same as one of the other 2:
= 1 * 1 **1/6 * 1/6
= 1/36
now
Find the number of ways this can happen:
to get Number of ways to get 3 out of the 4 dices the same :we will use combination formula
formula of combination= 4C3
combination= (4*3*2*1)/(3*2*1)
combination= 24/6=4
now Find the probability of getting 3 of the same:
P(3 of the same) = 1/36 * 4 = 1/9
Find the probability of NOT getting 3 of the same:
now subtract both
P(getting 3 NOT the same) = 1 - P(getting 3 of the same) = 1 - 1/9 = 8/9
hence 8/9 is the correct answer
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