Question

Factorise
$9x ^{4} - (x ^{2} + 2x + 1)$

Answer 1

hey mate.....

$9 {x}^{4} - ( {x}^{2} + 2x + 1)$
the ....... which is in brackets can be solved using( a + b) ^ whole square formula ..

$9 {x}^{4} - ( {x }^{2} + {1}^{2} + 2(x)(1)$
$9 {x}^{4} - (x + 1)(x + 1)$
9x^4 - (x+1 ) ^2

now u should use a^ - b^ formula....

(3x^)^2 - (x+1)^

(3x^2 - (x+1) ) ( 3x^2 + ( x+1))


hope it helps uu dear. . . . . . ☺☺

Answer 2

Step-by-step explanation:

9x^4 - (x^2 + 2x +1)

=9x^4 - x^2 +1^2 +2(x) (1)

=9x^4 - (x+1) (x+1)

=9x^4 - (x+1)^2

=(3x^2)^2 - (x+1)^2

=(3x^2 +x +1) (3x^2-x-1)