4. Find the area of a triangle two sides of which are 18cm and 10cm and the perimeter is
42cm.
5. Sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. Find its area.
qual sides is 12 cm Find
2am
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Answers
Ques :- Find the area of a triangle, two sides of which are 18cm and 10cm and the perimeter is 42 cm :
Answer :-
Given that,
Two sides of triangle are 18 cm and 10 cm.
Perimeter of triangle is 42 cm
Let, third side of triangle be x .
So,
Perimeter = 18 + 10 + x
42 = 28 + x
42 - 28 = x
x = 14
Third side of triangle is 14 cm.
Now,
s = 42/2
s = 21
Semi-perimeter is 21 cm.
Area of traingle :
√21 × (21 -18)(21 -14)(21 - 10)
√21 × 3 × 7 × 11
√3 × 7 × 3 × 7 × 11
3 × 7 √11
21 × √11
- Put √11 = 3.316
21 ×3.316
Area of triangle is 69.636 cm².
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Ques :- Sides of a triangle are in the ratio of 12:17:25 and its perimeter is 540cm. Find its area.
Answer :-
Given that,
Sides of triangle are in ratio 12:17:25.
Perimeter of triangle is 540 cm.
Let, Sides of triangle be 12x, 17x and 25x.
So,
Perimeter = 12x + 17x + 25x
540 = 54x
x = 540/54
x = 10
Sides:
12x = 12 × 10 = 120 cm
17x = 17 × 10 = 170 cm.
25x = 25 × 10 = 250 cm.
Now,
s = 540/2
s = 270
Semi-perimeter is 270 cm.
Area of traingle :
√270 × (270 - 120)(270 -170)(270 - 250)
√270 × 150 × 100 × 20
√2×5×3×3×3×2×5×5×3×2×2×5×5×2×2×5
2 × 2 × 2 × 5 × 5 × 5 × 3 × 3
Area of traingle is 9000 cm².
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Formulas used:-
• Perimeter of triangle = Sum of all sides
• Heron's formula that is
Area of traingle = √s(s - a)(s - b)(s - c)
where,
- s is semi-perimeter of triangle.
- a, b and c are sides of triangle.
• Semi-perimeter = Perimeter of triangle/2