4. Find the sum of the first 10 terms of the A.P. 6, 4, , ...
Find the 24th term of the A.P. 12, 16, 20, 24, ....
6. Which term of the A.P.2, 11,20, 29, ... is 560?
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4.....answer
n=10
a=6
d=4-6=-2
Sn=n/2[2a+(n-1)d]
Sn=10/2[2×6+(10-1)-2]
Sn=5[12+(9×-2)]
Sn=5(12-18)
Sn=5(-6)
Sn=-30
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5...answer
n=24
a=12
d=4
Tn=a+(n-1)d
T24=12+(24-1)4
=12+23×4
=12+92
=104..
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6..answer
tn=560
a=2
d=9
tn=a+(n-1)d
560=2+(n-1)9
560-2=(n-1)9
558=9n-9
558+9=9n
567=9n
n=567/9
n=63
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HOPE IT HELPS YOU......
REGARDS.....
ADDY_THAKUR......✌✌✌
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