Question

4. Find the zero of the polynomial in each of the following cases:
(i) p(x) = x + 3
(ii) p(x) = (x + 1) (x + 2)
(iii) p(x) = x2 – 3x + 2 (iv) p(x) = 2x² – 5x-3 2nd que pls​

Answer 1

Step-by-step explanation:

• put x+3=0 x=-3.
• (x+1)(x+2)=0 ,X2+3x+6=0

x=-1,-2

Answer 2

Answer:

answer

Step-by-step explanation:

P(x) =0

x+3=0

x= -3

P(x) =0

(x+3)(x+2)=0

x= -2,-3

(3) x2-3x+2 =0

x2-2x-x+2 =0

x(x-2)-1(x-2) =0

(x-2) (x-1) =0

x= 2,1

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