Question

4. If 4x²y², 8xy², p are in continued proportion , then find the value of p​

Answer 1

Answer:

p= 12asquare

Step-by-step explanation:

Answer 2

4x²y² , 8x²y² , p are in continued proportion

So

$\sf \large \frac{4 {x}^{2} {y}^{2} }{8x {y}^{2} } = \frac{8x {y}^{2} }{p}$

= 4x²y²p = 64x²y⁴

$\large \sf p = \frac{64 {x}^{2} {y}^{4} }{4 {x}^{2} {y}^{2} }$

P= 16y²