Math, asked by jaiprakashmaan761, 8 days ago

Please tell me. Who will give correct answer I'll make him or her brainliest.​​

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Answered by amansharma264
7

EXPLANATION.

x, y, z are positive real numbers.

p, q, r are natural numbers.

\sf \implies x^{p} = y^{q} = r^{z}

\sf \implies \dfrac{y}{x} = \dfrac{z}{y}

As we know that,

Let us considered as,

\sf \implies x^{p} = y^{q} = r^{z} = k \ (say).

\sf \implies x^{p}  = k

\sf \implies   x = k^{1/p} . - - - - - (1).

\sf \implies  y^{q} = k

\sf \implies  y = k^{1/q} . - - - - - (2).

\sf \implies  z^{r} = k

\sf \implies  z = k^{1/r} . - - - - - (3).

\sf \implies  \dfrac{y}{x} = \dfrac{z}{y}

\sf \implies  y^{2} = zx

Put the values in the equation, we get.

\sf \implies  (k^{1/q} )^{2} = (k^{1/p} ).(k^{1/r} )

\sf \implies  (k^{2/q} ) = (k^{1/p + 1/r} )

\sf \implies  \dfrac{2}{q} = \dfrac{1}{p} + \dfrac{1}{r}

Hence Proved.

Answered by Anonymous
36

Answer:

It is the correct answer.

Step-by-step explanation:

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