4. In Fig. 13.27, the congruent parts are marked.
Prove that tirangleABC = triangleABD.
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ad=bc
ab=ab
angle dac= angle cbd (1)
angle bac= angle abd (2)
addind 1 and 2,
dac+bac= cbd+abd
angle bad = angle abc
so, by sas ∆abc= ∆bad
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