Math, asked by sanhkuarasmita, 1 month ago

4. Point (3, 5) lies on the graph of the equation 3y = kx + 7. The value of k is;
a) 4/3
b) 8/3
c)3
d) 7/3​

Answers

Answered by pranitpatil6680
1

Answer:

4/3 is the answer of the equestion of the 3y=Kx +7.

Answered by TrustedAnswerer19
2

Answer:

If point (3, 5) lies on the graph of the equation

 \sf \: 3y = kx + 7

then the point will satisfy the equation.

so,

 \sf \:  \:  \: 3y = kx + 7 \\   \sf \implies \: 3 \times 5 = k \times 3 + 7 \\   \sf \implies \: 15 = 3k + 7 \\   \sf \implies \: 3k = 15 - 7 = 8   \\ \sf \implies \: k =  \frac{8}{3}

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