Question

* 4 points Find the equation of the circle which passes through the centre of the circle x2 + y2 + 8x + 10y - 7 = 0 and is concentric with the circle 2x2 + 2y2 - 8x - 12y - 9 = 0. - ​

Answer 1

Join / Login

Question

Equation of the circle which passes through the centre of the circle x2+y2+8x+10y−7=0 and is concentric with the circle 2x2+2y2−8x−12y−9=10 is

A

x2+y2−4x−8y−97=0

Your Answer

B

x2+y2−4x−6y−87=0

Correct Answer

C

x2+y2−2x−8y−95=0

D

None of these

Medium

Open in App

Solution

Verified by Toppr

Correct option is B)

First equation =x2+y2+8x+10y−7=0

its centre =(−4,−5)

Second equation of the circle

=2x2+2y2+8x−12y−9=0

its, centre =(2,3)

radius:=r2(2+4)2+(3+5)