Question

4. Two dice are rolled. Find the probability for the following everits :(i) A is the event that the sum of the digits on the uppermost faces is at least 10.(ii) B is the event that the sum of the digits on the uppermost faces is 13.(iii) Cis the event that the sum of the digits on the upper most faces is divisible by 5.(iv) D is the event that the sum of the digits on the uppermost faces is a multiple of 6.​

Answer 1

Explanation:

n(s)=36

event A =sum of digits on upper faces is at least 10 .

A={(4,6),(5,5),(5,6),(6,4),(6,5),(6,6)}.

n(A)=6

p(a)=n(a)/n(s)

p(A)=6/36=1/6

event B is not applicable for this example hence,

p(B)=0

event C={(1,4),(2,3),(3,2)(4,1)(4,6)(5,5)(6,4)}

n(B)=7

p(B)=n(b)/n(s)

p(b)=7/36

event D={(1,5)(2,4)(3,3)(4,2)(5,1)(6,6)}

n(d)=6

p(d)=n(d)/n(s)

p(d)=6/36=1/6