4. When a force of 50 kg is applied on a sledge of mass 500 kg. it is just about to start its motion, Calculate the coefficient of friction.
Answers
Answered by
2
We know frictional force f=μN where N=normal force=mg
Given sliding frictionμ=0.25
Thus, f=0.25×50×10=125N
Hence F
net
=F
app
−f=575−125=450N
Also we know ForceF=ma
a=
50
450
=9m/s
2
Given sliding frictionμ=0.25
Thus, f=0.25×50×10=125N
Hence F
net
=F
app
−f=575−125=450N
Also we know ForceF=ma
a=
50
450
=9m/s
2
Similar questions
Hindi,
2 months ago
Biology,
2 months ago
India Languages,
2 months ago
Social Sciences,
4 months ago
Math,
11 months ago
Science,
11 months ago