4 x square - 4 a square x + a raise to 4 minus b raised to 4 is equal to zero
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Answered by
13
4x^2 - 4a^2x + a^4 - b^4 = 0
4x^2 - 4a^2x + (a^2 + b^2) (a^2 - b^2) = 0
4x^2 - 2(a^2 + b^2)x -2(a^2 - b^2)x + (a^2 + b^2) (a^2 - b^2) = 0
2x [ 2x - (a^2 + b^2)] -(a^2 - b^2) [ 2x - (a^2 + b^2)] = 0
x = (a^2 + b^2)/2 or x = (a^2 - b^2)/2
pranjalxd12:
thanks dreamy
Answered by
9
Answer:
X=(a^2+b^2)/2 or, X=(a^2-b^2)/2
Step-by-step explanation:
hope it helps
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