Question

4 x square + 8 x + 4​

Answer 1

Answer:

4x^2+8x+4=0

If we factorize then we get it as,

4x^2+4x+4x+4=0

4x(x+1) +4(x+1) =0

(4x+4) (x+1) =0

so either 4x+4=0 or x+1=0

For 4x+4=0

4x=-4

x=-1

For x+1=0

x=-1

Therefore,

-1 is the solution of given quadratic equation.

I hope it helps.........

Answer 2

Answer:

The roots of the quadratic equation are -1 and -1

Step-by-step explanation:

$4 {x}^{2} + 8x + 4 = 0 \\ \\ On \: Simplification \:, \: we \: get \\ \\ {x}^{2} + 2x + 1 = 0 \\ x {}^{2} + x + x + 1 = 0 \\ x(x + 1) + (x + 1) = 0 \\ (x + 1) (x + 1) = 0 \\ x + 1 = 0 \\ x = - 1$

Thus the required roots are -1 and -1 .

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