Question

40+10(4y-8)-16(3y-5)=0​

Answer 1

Answer:

$40 + 10(4y - 8) - 16(3y - 5) = 0 \\ 40 + 40y - 80 - 48y + 80 = 0 \\ 40 - 4y =0 \\ 40 = 4y \\ 4y = 40 \\ y = \frac{40}{4} \\ y = 10$

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Answer 2

Answer:

40+10(4y-8)-16(3y-5)=0

40+40y-80-48y+80=0

40-80+80=48y-40y

40=8y

5=y

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