Question

41
12. Letf(x):= x2 for x € R, and let E := {XER: -1 < x < 0} and F := {reR: 0<x<1}.
Show that En F = {0} and f(En F) = {0}, while f(E) = f(F) = {YER: 0 Sy <1}.
Hence f(En F) is a proper subset of f(E) nf(F). What happens if 0 is deleted from the sets E
and F?​

Answer 1

Answer:

I know the answer.

Step-by-step explanation:

Follow me☺☺☺☺